Question

1) Show with the help of electronic configuration how the sodium chloride
is formed (Na-11, C1-17)
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Answer 1

Answer:

Atomic no. of Na=11

Electronic configuration of Na−2,8,1

No. of valence electrons =1

Atomic no. of Cl=17

Electronic configuration of Cl−2,8,7

No. of valence electrons =7

Na−Cl

Answer 2

Answer:

Na= 2,8,1

cl= 2,8,7

when NA AND Cl gets combined

-Na donates one electron to Cl and becomes positively charged

-Cl gains one electron from Na and becomes negatively charged

Na+ + Cl- = Nacl