√1-sin÷1+sin=sec-tan
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Answer:
Answer
(1−sinA)
(1+sinA)
×
(1+sinA)
(1+sinA)
=
1−sin
2
A
(1+sinA)
2
=
cos
2
A
(1+sinA)
2
=
cosA
1+sinA
=
cosA
1
+
cosA
sinA
=secA+tanA
Hence proved.
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