1 / sin 10 degree - 3 to the square root / cos 10 degree = 4?
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1/sin10°-√3/cos10°
by taking lcm
{cos10°-√3sin10°}/sin10°cos10°
rationalise by 2
2(cos10°-√3sin10°)/2sin10°cos10°
2(cos10°-√3sin10°)/sin20°
multiply and divide numerator by 2
4(1/2cos10°-√3/2sin10°)/sin20°
4sin20°/sin20°
=4
by taking lcm
{cos10°-√3sin10°}/sin10°cos10°
rationalise by 2
2(cos10°-√3sin10°)/2sin10°cos10°
2(cos10°-√3sin10°)/sin20°
multiply and divide numerator by 2
4(1/2cos10°-√3/2sin10°)/sin20°
4sin20°/sin20°
=4
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