Question

1-sin 10° sin 50° sin 70° find the value?
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Answer 1

Question :----

• Find the value of 1 -(sin10°*sin50°*sin70°)

Formula used :--------

• sin30° = 1/2
• sin@*sin(60-@)*sin(60+@) = 1/4[sin3@]

solution :--------

In Question sin 10° sin 50° sin 70° Let , @ = 10°

Than,

→ sin 10° sin 50° sin 70° = sin@*sin(60-@)*sin(60+@)

So, our value of @ = 10°

Hence,

→ sin 10° sin 50° sin 70° = 1/4 [sin3*10°]

→ sin 10° sin 50° sin 70° = 1/4[sin30°]

→ sin 10° sin 50° sin 70° = 1/4 * 1/2 = 1/8 ....

Putting this value in above Question we get,

→ 1-sin 10° sin 50° sin 70° = 1 - 1/8 = 7/8 (Ans)

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