Math, asked by debabratakarmakar6, 11 months ago

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(2/3x-3/2x-1)^2

Answers

Answered by nishantsingh22
11

Answer:

This is the answer 4/6x2-9x-3

Answered by jitendra420156
47

(\frac{2}{3x} - \frac{3}{2x} -1)^2 =\frac{61}{x^2} +\frac{5}{3x} +1

Step-by-step explanation:

Given,

(\frac{2}{3x} - \frac{3}{2x} -1)^2

=(\frac{2}{3x} )^2+(\frac{3}{2x})^2+1^2+2.( \frac{2}{3x}).(-1)+2.(-\frac{3}{2x}).(-1)+2.( \frac{2}{3x})(-\frac{3}{2x})

=\frac{4}{9x^2} +\frac{9}{4x^2} +1-\frac{4}{3x} +\frac{3}{x} -\frac{2}{x^2}

=\frac{61}{x^2} +\frac{5}{3x} +1

The given expression is one variable expression.

There is only one variable and that is x.

Variable: Variable is an unknown quantity whose the value of variable can be changes.

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