Question

1-sin^2(29)-sin^2(61) find the value

Answer 1

Answer:-

1 - Sin²29° - Cos²61°

Changing Cos to Sin we get,

= 1 - Sin²29° - Sin( 90° - 61°)

= 1 - Sin²29° - Sin²29°

= 1 - 0

= 1

Answer 2

Answer:

0

Step-by-step explanation:

1 - sin^2 (29) - sin^2 (61) [ as sin A= cos (90-A)]

=1- cos^2 (90-29) - sin^2 (61)

= 1- cos^2 (61) - sin^2 (61)

1 - cos^2 A= sin^2 A (identity)

=sin^2 (61)- sin^2 (61)

=0

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