Question

Let A, B, C, D be points on a vertical line such that AB = BC = CD. If a body is released from position A, the times of descent through AB, BC and CD are in the ratio.(a) 1: √3 - √2 : √3 + √2 (b) 1: √2 -1: √3 - √2(c) 1: √2 -1: √3 (d) 1: √2 : √3 -1

Answer 1

Answer:

B

Explanation:

Let ab = bc = cd = x

=> x = (1/2)gt1^2

2x = (1/2)gt2^2

3x = (1/2)gt3^2

=>

t1 = √(2x/g)

t2 = √(4x/g) and

t3 = √(6x/g)

=>

ratio of times of descent through ab, bc and cd

= t1 : (t2 - t1) : (t3 - t2)

= √(2x/g) : √(4x/g) - √(2x/g) : √(6x/g) - √(4x/g)

= √2 : (2 - √2) : (√6 - 2).