Math, asked by sonimeenakshi166, 5 months ago

1+ sin 2 A +cos 2 A
(v)
sin A +COS A
= 2 cos A.

Answers

Answered by Anonymous

14

Answer:

ANSWER

1+sin2A−cos2A1+sin2A+cos2A

=sin2A+1−(1−2sin2A)sin2A+1+2cos2A−1

=2sinAcosA+2sin2A2sinAcosA+2cos2A

=2sinA(cosA+sinA)2cosA(sinA+cosA)

=sinAcosA=cotA.

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