1+sin 2A+cos 2A÷1+sin 2A _cos 2A = cot A
Answers
Answered by
1
= cos 2A + cos 2A
÷ sin2a- sin-2a
= cot 2A - cot2a
(comon) :
= cot a (2-2)
= cotA
LHS =RHS
rachit751:
Consi math laga raha hai bhai
bhaii sahi solve krke bataa de bhaii plz
1 ki jagah cos²A+sin²A kar do
Aur sin2A and cos2A ka formula put kar do
Uske baad common bahar lo kat peet ke cotA bacega
thank u 100 much math guru
like u explain
Answered by
1
Put the formula of sin2A(=2sinA.cosA) and cos2A(=cos²A-sin²A) and
1=sin²A+cos²A
After cutting and adding the common things you get
(2cos²A+2sinA.cosA)÷(2sin²A+2sinA.cosA)
=cosA(2cosA+2sinA)÷sinA(2sinA+2cosA)
=cosA÷sinA
=cotA
1=sin²A+cos²A
After cutting and adding the common things you get
(2cos²A+2sinA.cosA)÷(2sin²A+2sinA.cosA)
=cosA(2cosA+2sinA)÷sinA(2sinA+2cosA)
=cosA÷sinA
=cotA
thank u
Similar questions