Question

1/sin^2x +cos^2x

options-- tanx + cotx
tanx-cotx
tanx.cotx
tanx+2cotx​

Answer 1

Answer:

Tanx. Cotx

1/sin^2x+cos^2x = 1/1 = 1

By the same thing,

Tanx. Cotx = (sinx/cosx).(cosx/sinx)

= sinx cosx/cosx sinx

= 1

Hence the answer is tanx. Cotx

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Answer 2

Answer:

Explanation:

Identities:

tan

x

=

sin

x

cos

x

cot

x

=

cos

x

sin

x

Substituting these in the LHS:

sin

x

cos

x

−

cos

x

sin

x

sin

x

cos

x

+

cos

x

sin

x

Adding the terms in numerator and denominator:

sin

2

x

−

cos

2

x

sin

x

cos

x

sin

2

x

+

cos

2

x

cos

x

sin

x

Multiplying by

(

cos

x

sin

x

)

sin

2

x

−

cos

2

x

sin

2

x

+

cos

2

x

Identity:

sin

2

x

+

cos

2

x

=

1

Substituting this in the denominator:

sin

2

x

−

cos

2

x

1

sin

2

x

−

cos

2

x

As required:

L

H

S

≡

R

H

S