1
) sin 300° cosec 1050° - tan (-120°)
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question=sin(360-60).cosec(720+330)-tan(-120)
-sin(60) cosec (330)+tan(120
-sin(60)/sin(360-30) +tan (180-60)
-sin(60)/(-sin30)) -tan60
sin60/sin30-tan60
(root3/2)/(1/2)-root3
root3-root3=0ans
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