Question

তলৰবােৰ উলিওৱা ?
(1) sin 39º - cos 51°
(ii) cos 48° - sin 42°
(iii)
cos ec25° - sec 65°
(iv) cot 34° - tan 56°
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Answer 1

Answer:

alll are zeroes ,by complementary property a+b=90°

Answer 2

Step-by-step explanation:

(1) sin(90-39)-cos51= cos51-cos51

(2)cos(90-48)-sin42=sin42-sin42

(3)cosec(90-25)-sec65=sec65-sec65

(4) cot(90-34)-tan56=tan56-tan 56

All is done by the equations like sin(90-A)=CosA

thank u