√1+sin A/ 1- sin A = sec A + tan A
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Sol: √1-sin A / 1+sin A = √(1-sin A) / (1+sin A ) x √(1-sin A) / (1-sin A ) = √(1-sin A)2 / (1-sin2 A ) = √(1-sin A)2 / cos2 A = (1-sin A) / cos A = (1/cos A - sin A/cos A) = sec A - tan A. √1-sin A / 1+sin A = sec A - tan A.
bharat9291:
this is wrong
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