Question

(1 + sin A) /cos A + cos A / (1+sin A) = 2 sec A​

Answer 1

Answer:

2seca

Step-by-step explanation:

=((1+sinA)square + (cosA))/(1+sinA)(cosA)

=(1+(sinA)square+(cosA)square+2(sinA))/(1+sinA)(cosA)

=(2+2sinA)/(1+sinA)(cosA)||because (sinA)square+(cosA)square=1

=2(1+sinA)/(1+sinA)(cosA)

=2/cosA

=2secA

Answer 2

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$\displaystyle \frac{1 + sin A}{cos A} + \frac{cos A}{1+sin A}= 2 sec A$

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⚫$\bf{\boxed{Some \ additional \ information}}$

$\boxed{\mathcal{</p><p></p><p>\begin{minipage}{19.08 em}</p><p></p><p>Fundamental \ Trigonometric \ Identities \\ \\</p><p></p><p>\sin^2\theta + \cos^2\theta=1 \\ \\</p><p></p><p>1+\tan^2\theta = \sec^2\theta \\ \\</p><p></p><p>1+\cot^2\theta = \text{cosec}^2 \, \theta</p><p></p><p>\end{minipage}</p><p></p><p>}}$

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