Math, asked by barbiefishuu, 1 year ago

(1-sin +cos square)=2(1+cos)(1+sin)​

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Answered by shadowsabers03
2

         

\Rightarrow\ (1-\sin\theta +\cos\theta )^2 \\ \\ \Rightarrow\ 1+\sin^2\theta+\cos^2\theta-2\sin\theta-2\sin\theta \cdot \cos\theta+2\cos\theta \\ \\ \Rightarrow\ 1+1-2\sin\theta-2\sin\theta \cdot \cos\theta+2\cos\theta \\ \\ \Rightarrow\ 2-2\sin\theta-2\sin\theta \cdot \cos\theta+2\cos\theta \\ \\ \Rightarrow\ 2(1-\sin\theta-\sin\theta \cdot \cos\theta+\cos\theta) \\ \\ \Rightarrow\ 2(1-\sin\theta+\cos\theta-\sin\theta \cdot \cos\theta) \\ \\ \Rightarrow\ 2(1(1-\sin\theta)+\cos\theta(1-\sin\theta))

\Rightarrow\ 2(1+\cos\theta)(1-\sin\theta) \\ \\ \\ $Hence proved! \\ \\ \\ Plz ask me if you've any doubt. \\ \\ \\ \\ \\ Thank you. :-))

           


barbiefishuu: thank you buddy
Answered by Anonymous
0

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