Question

1 - sin square theta by 1 + cos theta​

Answer 1

$\frac{1 - {sin}^{2} \theta }{1 + cos \theta} \\ \\ = \frac{{cos}^{2} \theta}{1 + cos\theta} \\ \\ = cos\theta - 1 + \frac{1}{1 + cos\theta}$

hope it helps