Question

1 + sin x+cos x/1-sin x+cos x=1+sjn x/cos x​

Answer 1

Answer:

sin(x)+cos(x)−1−sin(x)cos(x)=0

sin(x)[1−cos(x)]−(1−cos(x))=0

(1−cos(x))(sin(x)−1)=0

Hence

cos(x)=1 or x=2kπ and

sin(x)=1 or x=2kπ+

π

•

2

Fork=0,x=0 or π/2⇒ options A,C,D are true