Question

1/sin10-√3/cos10=4 prove it

Answer 1

$\huge \boxed{answer}$

L.H.S=>1/sin10-3(root)/cos10

=> cos10°- 3(root)sin10° by sin10°.cos10°

2[1/2×cos10°-3 (root)/2×sin10° by sin10°.cos10°

here multiplied numerator and denominator with1by 2

=2(sin30°.cos10°- cos30°.sin10°) by sin10°.cos10°

=2×sin(30°-10°) by sin10°.cos10°

=2 sin20° by sin10°.cos10°

=4 sin20° by 2 sin10°.cos10°

=4 sin20° by sin20° (after cancellation)

=4

R.H.S✔

Answer 2

L.H.S=>1/sin10-3(root)/cos10

=> cos10°- 3(root)sin10° by sin10°.cos10°

2[1/2×cos10°-3 (root)/2×sin10° by sin10°.cos10°

here multiplied numerator and denominator with1by 2

=2(sin30°.cos10°- cos30°.sin10°) by sin10°.cos10°

=2×sin(30°-10°) by sin10°.cos10°

=2 sin20° by sin10°.cos10°

=4 sin20° by 2 sin10°.cos10°

=4 sin20° by sin20° (after cancellation)

=4

R.H.S✔