Question

(1-sin²θ)sec²θ = -----​

Answer 1

Step-by-step explanation:

we know that: sin^2theta+cos^2theta=1

so, 1-sin^2theta= cos^2theta

= cos^2theta×sec^2theta

we know that: sec^2theta=1/cos^2theta

so, cos^2theta×1/cos^2theta=1

ans: 1

hope it helps you!

Answer 2

Step-by-step explanation:

(1-sin2¤ ) = Cos2¤

(1-sin2¤ ) = Cos2¤Cos2© * 1/cos2¤= 1

I hope it helps you

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