(1 + sin20 + cos20)2 = 4cos²0(1 + sin20)
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Answered by
2
Correct option is
A
1745
Given
sin20
o
1
+
3
cos20
o
1
=2kcos40
o
....(1)
Consider,
sin20
o
1
+
3
cos20
o
1
=
3
sin20
o
cos20
o
3
cos20
o
+sin20
o
=
4
3
sin40
o
2
3
cos20
o
+
2
1
sin20
o
=
(
3
/4)sin40
o
sin60
o
cos20
o
+cos60
o
sin20
o
=
4
3
sin40
0
sin80
0
=
3
8
cos40
o
Answer:
So, by (1), we get
k=
3
4
⇒3k
2
=16
So 18k
4
+162k
2
+369=1745
Step-by-step explanation:
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