1+sin2theta = (sin theta + cos theta) ^2
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Step-by-step explanation:
1+sin2A=(sinA+cosA)^2
=sin^2A+cos^2A+2sinAcosA
We know that ,
sin^2A+cos^2A=1 and sin2A =2sinAcosA
Now,
1+sin2A=1+2sinAcosA
1+sin2A=1+sin2A
proved LHS=RHS
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