Question

1+sin2theta = (sin theta + cos theta) ^2​

Answer 1

Step-by-step explanation:

1+sin2A=(sinA+cosA)^2

=sin^2A+cos^2A+2sinAcosA

We know that ,

sin^2A+cos^2A=1 and sin2A =2sinAcosA

Now,

1+sin2A=1+2sinAcosA

1+sin2A=1+sin2A

proved LHS=RHS