1+sin2x-cos2x÷1+sin2x+cos2x=tanx
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(i)
(1-cos2x + sin2x) / (1+cos2x+sin2x)
= [1-1+2(sinx)^2 + 2sinxcosx] / [1 + 2(cosx)^2 -1 + 2sinxcosx]
= (sinx/cosx) * [sinx+cosx]/[cosx + sinx]
=sinx/cosx
=tanx
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