solve the simultaneous equation graphically X + 2y is equal to 5 Y is equal to minus 2 x minus 2
Answers
Answer:
Step-by-step explanation:
To solve these equations graphically
Firstly solve these two individually,by putting the value of x and calculate the value of y.
1) x+2y = 5
put y=0,then x=5 =>(5,0)
put x=0,then y=2.5 =>(0,2.5)
2)y=-2x-2
put y=0,then x=-1 =>(-1,0)
put x=0,then y=-2 =>(0,-2)
On sketching these points ,both lines meet at (-3,4)
So, the solution of these equations are
x=-3
y=4
Hope it helps you.
Answer:
x+2y = 5
x+2y = 5put y=0,then x=5 =>(5,0)
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)On sketching these points ,both lines meet at (-3,4)
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)On sketching these points ,both lines meet at (-3,4)So, the solution of these equations are
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)On sketching these points ,both lines meet at (-3,4)So, the solution of these equations arex=-3
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)On sketching these points ,both lines meet at (-3,4)So, the solution of these equations arex=-3y=4
x+2y = 5put y=0,then x=5 =>(5,0)put x=0,then y=2.5 =>(0,2.5)2)y=-2x-2put y=0,then x=-1 =>(-1,0)put x=0,then y=-2 =>(0,-2)On sketching these points ,both lines meet at (-3,4)So, the solution of these equations arex=-3y=4Hope it helps you.