Question

√(1+sinA/1-sinA) + √(1-sinA/1+sinA) = 2secA

Answer 1

I hope it will help u

Answer 2

Solution:

LHS = $\sqrt{(\frac{1+sinA}{1-sinA})}+\sqrt{(\frac{1-sinA}{1+sinA})}$

= $\frac{\sqrt{(1+sinA)^{2}}+\sqrt{(1-sinA)^{2}}}{\sqrt{(1-sinA)}\cdot\sqrt{(1+sinA)}}$

= $frac{1+sinA+1-sinA}{\sqrt{1-sin^{2}A}}$

= $\frac{2}{\sqrt{cos^{2}A}}$

= $\frac{2}{cosA}$

= $2secA$

= RHS

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