1-SinA/1+sinA=(seca-tana) ^2
Answers
Answered by
7
shallu143:
thnk uh so much
Answered by
8
Step-by-step explanation:
Answer
(sec(a)−tan(a))
2
=
1+sin(a)
1−sin(a)
lhs
(
cos(a)
1
−
cos(a)
sin(a)
)
2
cos
2
(a)
(1−sin(a))
2
1−sin
2
(a)
(1−sin(a))
2
(1−sin(a))×(1+sin(a))
(1−sin(a))×(1−sin(a))
1+sin(a)
1−sin(a)
henceproved
NOTE
1)sec(x)=
cos(x)
1
2)tan(x)=
cos(x)
sin(x)
3)sin
2
(x)=1−cos
2
(x)
4)(α
2
−β
2
)=(α−β)×(α+β)
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