Question

1+sinA/1-sinA=(secA+tanA)^2​

Answer 1

Step-by-step explanation:

√1+sinA/1-sinA=√(1+sinA)²/cos²A

√1+sinA/1-sinA=(1+sinA)/cosA

√1+sinA/1-sinA=secA+tanA

1+sinA/1-sinA=(secA+tanA)²