Question

√1-sinA /1+sinA=？what will be the answer

Answer 1

√1-sin A / 1+sin A

= √(1-sin A) / (1+sin A ) x √(1-sin A) / (1-sin A )
= √(1-sin A)2 / (1-sin2 A )
= √(1-sin A)2 / cos2 A
= (1-sin A) / cos A
= (1/cos A - sin A/cos A)
= sec A - tan A.

√1-sin A / 1+sin A = sec A - tan A.