Math, asked by itsrfa36, 19 days ago

( 1 + sinA )² + ( 1 - sinA )²/ 1 + sin²A = 2

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Answered by bhanuprakashmuddala

1

Answer:

((1+sinA)²+(1-sinA)²)/(1+sin²A)

=((1+sin²A+2sinA)+(1+sin²A-2sinA))/(1+sin²A)

=(2+2sin²A)/(1+sin²A)

=(2(1+sin²A))/(1+sin²A)

=2

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