Math, asked by reinasalvaje8, 2 months ago

1-sina/sina+cosa/1-sina=2seca

Answers

Answered by suchismitadash7542
0

Answer:

correct qs is 1-sina/cosa+cosa/1-sina

 \frac{(1 -   \sin(a))(1 -   \sin(a)) +  \cos(a)  \cos(a)   }{ \cos(a)(1 -  \sin(a) ) }  \\  =  \frac{1 -  \sin(a) -  \sin(a) +  { \sin }^{2}(a) +  \cos(a)  \cos(a)    }{ \cos(a)(1 -  \sin(a))  }  \\  =  \frac{1 - 2 \sin(a) +   { \sin }^{2}(a) + {cos}^{2}(a)  }{\cos(a)(1 -  \sin(a))}  \\  =  \frac{1 - 2 \sin(a) + 1 }{\cos(a)(1 -  \sin(a))}  \\  =  \frac{2 - 2 \sin(a) }{\cos(a)(1 -  \sin(a))}  \\  =  \frac{2(1 -  \sin(a)) }{\cos(a)(1 -  \sin(a))}  \\  =  \frac{2}{ \cos(a) }  = 2 \sec(a)

Similar questions