Question

1-sinx =__ ?
1+sinx= __?
1-cosx=__?
1+cosx=__?

plz ans this

Answer 1

hlo mate Hope it satisfied you


=> sin²x + cos²x = 1

1)=> cos²x = 1-sin²x.

=>cos²x=(1-sinx)(1+sinx)

so=>(1-sinx)=cos²x/(1+sinx)

and =>(1+sinx)=cos²x/(1-sinx)

2))=>sin²x = 1-cos²x

=> sin²x = (1-cosx)(1+cosx)

so => (1-cosx) =sin²x /(1+cosx)

and => (1+cosx)= sin²x / (1-cosx)