Math, asked by ricky789, 4 months ago

1-SinX/1+SinX=CosecX-1/CosecX+1​

Answers

Answered by Nksystem
1

Answer:

1-sinx / 1+sinx = cosecx -1 / cosecx +1

 \frac{1 -  \sin(x) }{1 +  \sin(x ) }  \:  \times  \frac{1 -  \sin(x) }{1 -  \sin(x) }  \:  =    \frac{cosecx - 1}{cosecx + 1 }  \\  \frac{1 -  \sin(x ) \times  1- \sin(x)  }{1  +  \sin(x)  \times 1 -  \sin(x )  }   =   \frac{ \csc(x - 1) }{ \csc( x + 1) }

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