1+Sinx/n=7. Prove that
Answers
Answered by
9
sinx/n+1 = 7
sinx = 7n+7
we know that the range of sinx is from -1 to 1
so 7n+7 also lies in between -1 and 1.
-1<= sinx <=1
-1<=7n+7<=1
subtracting 7 on both the sides
-8<=7n<= -6
dividing 7 on both the sides
-8/7<=n<= -6/7
now multiplying - sign on both the sides, so the
equality sign changes
8/7>=n>=6/7
hope u understand
sinx = 7n+7
we know that the range of sinx is from -1 to 1
so 7n+7 also lies in between -1 and 1.
-1<= sinx <=1
-1<=7n+7<=1
subtracting 7 on both the sides
-8<=7n<= -6
dividing 7 on both the sides
-8/7<=n<= -6/7
now multiplying - sign on both the sides, so the
equality sign changes
8/7>=n>=6/7
hope u understand
Answered by
5
1 + sin x =7n
sin x=7n -1
therefore, sin x is equals to
7n- 1
sin x=7n -1
therefore, sin x is equals to
7n- 1
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