Question

Find the volume of ammonia liberated when three grams of hydrogen reacts with twenty eight grams of nitrogen at stp

Answer 1

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Given:

3 grams of hydrogen reacts with 28 grams of nitrogen at STP

To find:

Volume of ammonia liberated = ?

Explanation:

N2 + 3H2 -> 2NH3

Mole = Mass/Molar mass

Mole of nitrogen = 28/28 = 1 mole

Mole of hydrogen = 3/2 = 1.5 mole

To find Limiting reagent formula =

mole/ stoichiometry coefficient

For nitrogen = 1/1 = 1

For hydrogen = 1.5/3 = 0.5

So the limiting reagent is hydrogen

3 mole hydrogen gives 2 mole ammonia

1.5 mole hydrogen gives 2×1.5/3 = 1 mole ammonia

For volume of ammonia

Mole = Volume/22.4

1 ×22.4 = Volume

22.4 Litre = volume

Answer:

Thus, volume of ammonia liberated is 22.4 litre