1. solve,. √2x²+x+√2=0.
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Answer:
- 1 ± i√7/2√2.
Step-by-step explanation:
√2x²+x+√2=0.
On comparing the given equation with ax2 + bx + c = 0, we know that
x = -b±√b²-4ac/2a
Now a =√2 , b = 1, and c = √2
thus the required solutions are
x = -1 ± √1 - 8/2√2
= -1±√-7/2√2
= - 1 ± i√7/2√2.
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