Math, asked by bhuvi0626, 9 months ago

1. solve,. √2x²+x+√2=0.​

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Answers

Answered by spiderman2019
3

Answer:

- 1 ± i√7/2√2.

Step-by-step explanation:

√2x²+x+√2=0.​

On comparing the given equation with ax2 + bx + c = 0, we know that

x = -b±√b²-4ac/2a

Now a =√2 , b = 1, and c = √2

thus the required solutions are

         x = -1 ± √1 - 8/2√2

           = -1±√-7/2√2

           = - 1 ± i√7/2√2.

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