1) solve 3(x+3) -2(x-1) =5(x-5)
2) solve 10x+3y=75, 6x-5y=11
3) The sum of numerator and denominator of a fraction is 8.If 3 is added to both numerator and denominator, the fraction becomes 3/4.find the fraction
4) the sum of digits of a two digit number is 15.the number obtained by interchanging the digits exceeds the given number by 9.find the number.
5) find the quadratic equation whose roots are 2+√3, 2-√3
6) if the root if the equation are equal then fund the value of k
Kx(x-2) +6=0
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Answer:
1) 3(x+3)-2(x-1)=5(x-5)
3x+9-2x+2=5x-25
x+11=5x-25
x-5x= -11-25
-4x= -36
x= -36/-4
x=9
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