Math, asked by jaeminana, 4 months ago

1.Solve 3t+ 9⁄7=-5⁄7 +t
t=1
t=-1
t=3
2.Solve t⁄5 =7
t=30
t=35
t=40
3.The sum of three consecutive multiples of 7 is 252. Find these multiples.
84,91,98
77,83,92
77,84,91

Answers

Answered by tennetiraj86
3

Step-by-step explanation:

1.Solution :-

Given equation is

3t + (9/7) = (-5/7)+t

=> 3t -t = (-5/7)-(9/7)

=> 2t = (-5-9)/7

=> 2t = -14/7

=> 2t = -2

=> t = -2/2

=> t = -1

Answer:-

The value of t = -1

2. Solution:-

Given equation is t/5 = 7

=> t = 7×5

=> t = 30

Answer:-

The value of t = 30

3.solution:-

Let the three consecutive multiples of 7 are

X,X+7,X+14

Their sum= X+X+7+X+14 = 3X+21

According to the given problem

The sum of the three consecutive multiples of 7 = 252

=> 3X+21 = 252

=> 3X =252-21

=> 3X= 231

=> X =231/3

=> X=77

=> X+7 = 77+7=84

=> X+14 = 77+14 = 91

Answer:-

The three consecutive multiples of 7 are 77,84,91

Similar questions