Math, asked by mikicocomibt2, 2 months ago

1 Solve:

3x-2 (x+3)/3 = 16 -x+2 /2​

Answers

Answered by abhishekshibu9267
0

Answer:

3x^2 + 31x -54 = 0

Step-by-step explanation:

(3x-2)(x+3)/3 = 16 (-x+2) /2​

(3x-2)(x+3)/3 = 8(-x+2)

(3x-2)(x+3)/3 = -8x+16

3x^2+9x-2x-6 = 3(-8x+16)

3x^2+7x-6 = -24x+48

3x^2+7x+24x-6-48 = 0

3x^2 + 31x -54 = 0

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