Question

1. Solve 3x-y=3 and 9x-6y=12 linear equations by substituting method​

Answer 1

Answer:

We can find x and y intericepts and thus of the two points on the lines (1), (2) x + y = 7 … (1), x – y = 3 … (2) To draw the graph of (1) Put x = 0 in (1) 0 + y = 7 ⇒ y = 7 Thus A (0, 7) is a point on the line Put y = 0 in (1) x + 0 = 7 ⇒ x = 7 Thus B (7, 0) is another point on the line Plot A and B. Join them to produce the line (1). To draw the graph of (2), we can adopt the same procedure. When x = 0,(2) ⇒ x – y = 3 0 – y = 3 ⇒ y = -3 P (0, -3) is a point on the line. Put y = 0 in (2); x – 0 = 3 x = 3 ∴ Q (3, 0) is another point on the line (2) Plot P, Q The point of intersection (5, 2) of lines (1), (2) is a solution (ii) 3x + 2y = 4 … (1) 9x + 6y= 12 … (2) To draw the graph of (1) Put x = 0 in (1) ⇒ 3 (0) + 2y = 4 2y = 4 y = 2 ∴ A (0, 2) is a point on the line (1) Put y = 0 in (1) ⇒ 3x + 2(0) = 4 3x = 4 x = 4343 = 1.3 ∴ B (1.3, 0) is another point on the line (1) Plot the points A, B. Join them to produce the line (1) To draw the graph of (2) Put x = 0 in (2) ⇒ 9 (0) + 6y = 12 6y = 12 y = 2 Read more on Sarthaks.com - https://www.sarthaks.com/965615/solve-graphically-i-x-y-7-x-y-3-ii-3x-2y-4-9x-6y-12-0