1) Solve for x i) 3x^2-2x-5=0
Answers
Answer:
3
x
+
5
)
=
0
x
=
−
(
5
3
)
x
−
1
=
0
x
=
1
Hence, solution is
x
=
−
(
5
3
)
or
x
=
1
Explanation:
The question gives you an equation
3
x
2
+
2
x
−
5
=
0
.
Hence to solve the equation, factorise.
3
x
2
+
2
x
−
5
=
0
(
3
x
+
5
)
(
x
−
1
)
=
0
The 2 factors of the equation are
(
3
x
+
2
)
and
(
x
−
1
)
.
With
(
3
x
+
5
)
=
0
and
(
x
−
1
)
=
0
Solve for
x
to find the solutions.
Step-by-step explanation:
Step-by-step explanation:
3x
2
−2x−5
=0?
view step
3x^{2}+ax+bx-5
ab
a+b=-2
a+b=−2
ab=3\left(-5\right)=-15
ab=3(−5)=−15
view step
ababa+b-15
1,-15
1,−15
3,-5
3,−5
view step
1-15=-14
1−15=−14
3-5=-2
3−5=−2
view step
-2
a=-5
a=−5
b=3
b=3
view step
3x^{2}-2x-5
\left(3x^{2}-5x\right)+\left(3x-5\right)
\left(3x^{2}-5x\right)+\left(3x-5\right)
(3x
2
−5x)+(3x−5)
view step
x3x^{2}-5x
x\left(3x-5\right)+3x-5
x(3x−5)+3x−5
view step
3x-5
\left(3x-5\right)\left(x+1\right)
(3x−5)(x+1)
view step
3x-5=0x+1=0
x=\frac{5}{3}
x=
3
5
x=-1
x=−1
is true