Question

1. Solve :-

$\sf (a) - 5 \frac {1}{3} - 7\ \textless \ br /\ \textgreater \ \\ \\ \sf (b) \: \frac{4}{11} + \frac{5}{9} \ \textless \ br /\ \textgreater \ \sf \\ \\ \sf(c) \: \frac{2}{17} \: \div \: \frac{18}{56}$



2. From the sum of 2x + y - 11 and -4x - 3y + 7 subtract the sum of x + y + 5 and 5x - 7y + 3.

3. Construct a △ABC given ∠A = 30° ∠B = 50° and AB = 5.6.

4. Simplify and find the value at x = 5.

(a) 3 ( 2x + 7 ) - 4x - 11.
(b) 4x - 3 + 5 ( 2x - 4 ).

5. Define :-

(a) Adjacent angles
(b) Linear pair angles​

Answer 1

Step-by-step explanation:

Solutions:-

1)-5 1/3 -7

=>(-16/3)-7

=>(-16-21)/3

=>-37/3

-5 1/3 -7=-37/3

b)4/11+5/9

LCM of 11 and 9=99

=>(36+55)/99

=>91/99

4/11 + 5/9 = 91/99

c)2/17 ÷ 18/56

=>2/17 ÷ 9/28

=>(2/17)/(9/28)

=>(2/17)×(28/9)

=>(2×28)/(17×9)

=>56/153

2/17 ÷ 18/56 = 56/153

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2)Sum of 2x + y - 11 and -4x - 3y + 7

=>2x + y -11 -4x -3y +7

=>(2x-4x)+(y-3y)+(-11+7)

=>-2x-2y-4

sum of x + y + 5 and 5x - 7y + 3.

=>x + y + 5 +5x -7y +3

=>(x+5x)+(y-7y)+(5+3)

=>6x-6y+8

From the sum of 2x + y - 11 and -4x - 3y + 7 subtract the sum of x + y + 5 and 5x - 7y + 3.

=>(-2x -2y -4) - (6x -6y +8)

=>-2x -2y -4 -6x + 6y -8

=>(-2x -6x)+(-2y+6y)+(-4-8)

=>-8x +4y -12

Therefore the answer = -8x +4y -12

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3) See the above attachment

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4)

a)3 ( 2x + 7 ) - 4x - 11.

=>6x + 21 -4x -11

=>(6x -4x)+(21-11)

=>2x+10

Put x=5 then the value is

=>2(5)+10

=>10+10

=>20

b)4x - 3 + 5 ( 2x - 4 ).

=>4x -3 + 10x -20

=>(4x +10x)+(-3-20)

=>14x -23

Put x=5 then the value is

=>14(5)-23

=>70-23

=>47

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5)Adjacent angles :-

Angles having the same vertex and a common side and which lie on the opposite sides of the common side are called adjacent angles.

Liner pair:-

Two adjacent angles are said to form a linear pair of angles if they lie on the same straight line and the two non common arms are opposite rays.