The resistance of a wire is10 . Its length is increased by 10% by stretching. The new resistance will now be
(a)
12
(b)
1.2
(c)
13
(d)
11
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1
Answer:
the resistance of wire is 10 ohm
Let say Earlier Length = L
& Area = A
=> Volume = AL
R = ρ L/A
=> ρ L/A = 10
length is increased by 10% by stretching
=> new Length = L + (10/100)L = 1.1 L
Volume Remains Same
=> New A rea = AL/ 1.1 L = A/1.1
New Resistance = ρ 1.1 L /(A /1,.1)
= 1.21 ρL/A
= 1.21 * 10
= 12.1 Ω
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