1. Solve the following equations and verify your answer.
(i) 5x + 3 = 8
(ii) -3x = 24
(iv) - 4x = -16
(iii) 5x = -10
(v) 4x - 9 = 11
(vi) 8x - 8 = 12x
(vii) - +1 =
= - + 3
(vii) - x = 27
*+
4
5
(ix) 7x - 13 = 12 - 5x -5
(x) 3(x - 12) = 8
2x + 3 3
4x-1 1
(xi)
= 4-
2
x +1 3
2. Solve the following equations:
(i) 8(x – 3) - 2(3 - x) = 2(x+2) – 5(5 - x) (i) 5(x - 3) - 7(6- x) = 21 - 3(8 - x)
(iii) x2 - (x - 1)2 = 2
(iv) (x - 4)(2x + 3) = 2x2
x + 3
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AnswerGiven equation are
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AnswerGiven equation are 2x1
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AnswerGiven equation are 2x1 − y1
AnswerGiven equation are 2x1 − y1 =−1...(i)×
AnswerGiven equation are 2x1 − y1 =−1...(i)× 2
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 +
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]Multiplying eqn (i) by the coefficient of
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]Multiplying eqn (i) by the coefficient of y
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]Multiplying eqn (i) by the coefficient of y1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]Multiplying eqn (i) by the coefficient of y1
AnswerGiven equation are 2x1 − y1 =−1...(i)× 21 x1 + 2y1 =8...(ii)×,1x,y=0[ x,y both are denominator and symmetric no need to convert into linear equation hence can be eliminated directly]Multiplying eqn (i) by the coefficient of y1 in (ii) and vice versa m we
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