Math, asked by aditya1020956, 6 months ago

1. Solve the following questions.
1. PM = 10 cm, A(APQS) = 100 sq.cm. A(AQRS) = 110sq.cm then find NR.

Answers

Answered by sudheeshkumarsankara

Answer:

PM=10 cm A(ΔPQS)=100 sq.cmA(ΔQRS)=110 sq.cm then NR = 11 cm.

Step-by-step explanation: Area of Δ PQS = (1/2) QS * PM. A(ΔPQS)=100 cm² (1/2) QS * PM = 100. => (1/2) * QS * 10 = 100. => QS = 20. Area of Δ QRS = (1/2) QS * PM. A(ΔQRS)=110 cm² (1/2) QS * NR = 110. ...

=> NR = 11 cm. as per fig A(ΔQRS)=150 cm² then NR = 15 cm.

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1. Solve the following questions.1. PM = 10 cm, A(APQS) = 100 sq.cm. A(AQRS) = 110sq.cm then find NR. ​

Answers

1. Solve the following questions.
1. PM = 10 cm, A(APQS) = 100 sq.cm. A(AQRS) = 110sq.cm then find NR.