Question

1) Solve the following simultaneous equations:-
2a + b = 6 ; 5a + b = 10 ​

Answer 1

Answer:

Step-by-step explanation:

Complete the following activity to solve the simultaneous equations. ... 2a = 4 ⇒ a = 2. Putting the value of a = 2 in (II) 5b = 22 - 2 = 20 ⇒b = 205=4 ... of y = 1 in (II) we get x+5(1)=4⇒x+5=4⇒x=4-5=-1. Thus, (x, y) = (−1, 1) (6) 13x+y=103 .

Answer 2

Answer:

2a + b = 6--------(1)

5a + b = 10 -----(2)

subtract equation (1) from (2).

[5a+b=10] - [2a+b=6]

3a = 4

a = 4/3

put a = 4/3 in equation (2)

5(4/3)+b=10

20/3+b=10

b= 10×3/20

b=3/2

hence,

solution = (a,b) = (4/3,3/2)