Chemistry, asked by gargiguptag2, 5 months ago

Paga No.1
The spacing between the lines in the miocowane
spectrum of HBr is 16.94 cm. calculate the
bond length of the molecule.

Answers

Answered by Afreenakbar

Answer:

The bond length of the HBr molecule is approximately 8.47 cm based on the given spacing between the lines in the microwave spectrum.

Explanation:

We can use the following formula to determine the HBr molecule's bond length using the microwave spectrum's provided line spacing:

$Bond \: length (d) = \frac{\lambda}{ (2 \Delta \nu)}$

Where:

λ is the wavelength of the transition

Δν is the spacing between the lines

The distance between the lines (Δν) in this instance is specified as 16.94 cm. Before moving on, we must convert this to frequency (ν).

In terms of cm/s, the speed of light (c) is roughly 3 x 10¹⁰cm/s. As a result, the frequency can be determined as follows:

$\nu = \frac{\Delta\nu}{\lambda}$

Let's now assume that the wavelength ( λ ) represents the average value of the line spacing. Therefore, λ = 16.94 cm.

Putting the values in the equation as substitutes:

$\nu = \frac{16.94 cm}{16.94 cm}$

ν = 1 cm

At this point, we can determine the bond length (d):

$Bond \: length (d) = \frac{\lambda}{ (2 \Delta \nu)}$

$d = \frac{ (16.94 cm) }{ (2 \times 1 cm)}$

$d = \frac{ 16.94 cm^{2} }{ 2}$

d = 8.47 cm

Therefore, the bond length of the HBr molecule is approximately 8.47 cm based on the given spacing between the lines in the microwave spectrum.