Question

(√?-1)squar2=8-√28please solve

Answer 1

${( \sqrt{x} - 1) }^{2} = 8 - \sqrt{28} \\ x + 1 - 2 \sqrt{x} = 8 - 2 \sqrt{7} \\ x - 2 \sqrt{x} = 7 - 2 \sqrt{7} \\ on \: comparing \\ x = 7$

Answer 2

Hey



( √ x - 1 ) ² = 8 - √28



=> x + 1 - 2√x = 8 - 2√7


=> x - 2√x = 7 - 2√7


Here see ,


When we compare both the LHS and RHS ,


We get that


x = 7


and 2√x = 2√7


So ,

in place of x , 7 is coming .


So , x = 7



thanks :)