1 square minus b square formula
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1^2-b^2 = (1+b)(1-b)
it comes from
(a^2-b^2) = (a+b)(a-b)
it comes from
(a^2-b^2) = (a+b)(a-b)
Answered by
0
(1)^2-(b)^2
Using a^2-b^2=(a+b)(a-b)
=>(1+b)(1-b)
Using a^2-b^2=(a+b)(a-b)
=>(1+b)(1-b)
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