Question

(1) State kohlrausch's haw. Molar conductivity at infinite dilution
for NH4Cl, NaOH and NaCl Solution at 298 K are 110, 100 and 105
Scm2mol-1 respectively. Calculate the molar conductivity of
NH4OH solution. (3)​

Answer 1

Answer:

first thanks me then I'll give you the answer

Answer 2

Answer:

answr

search

What would you like to ask?

CHEMISTRY

Equivalent conductance at infinite dilution, λ

0

of NH

4

Cl, NaOH and NaCl are 128.0, 217.8 and 109.9 ohm

−1

cm

2

eq

−1

respectivley. The equivalent conductance of 0.01 N NH

4

OH is 9.30 ohm

−1

cm

2

eq

−1

, then the degree of ionization of NH

4

OH at this temperature would be :

Share

Study later

ANSWER

According to Kohlrausch law of independent migration of ions, the molar conductivity of an electrolyte at infinite dilution is equal to the sum of the contributions of the molar conductivities of its ions.

Hence,

Λ

eq

∞

(NH

4

OH)=Λ

eq

∞

(NH

4

Cl)+Λ

eq

∞

(NaOH)−Λ

eq

∞

(NaCl)

Substitute values in the above equation

Λ

eq

∞

(NH

4

OH)=128.0+217.8−109.9

=235.9ohm

−1

cm

2

eq

−1

The degree of dissociation is the ratio of the equivalent conductance at given concentration to the equivalent conductance at zero concentration. Hence,

α=

Λ

eq

∞

Λ

eq

=

235.9

9.30

=0.04.

Option A is correct.