Question

1. sum of three prime numbers is 100.If one of them exceeds another by 36, then one of the numbers is....
1. 7
2. 29
3. 41
4. 67

2. let x,y and z be distinct integers where x and y are odd and positive, and z is even and positive. Which of the following statements cannot be true?
1. (x-z)^2 × y is even
2. ( x-z)y^2 is odd
3. (x-z)y is odd
4. (x-y)^2 × z is even

Plz answer me... its a bit urgent....
thanks

Answer 1

heya folk !!!!

1.Let three prime numbers are X, X+36 and Y.

According to questions,

X +X +36 +Y = 100.

2X +Y = 64 ------------------------- (1)

All three are prime number so 2X should be a even number. Also, to get sum as 100 (even number) Y should be an even prime number i.e 2.

Putting Y = 2

2X +2 = 64

X = 31

Thus, prime numbers are 31, 67 and 2.

4 is correct option

2.1 is correct option