Question

1. Suppose we throw a dice once. i) What is the probability of getting a number greater than 4? ii) What is the probability of getting a number less than or equal to 4?

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Answer 1

Step-by-step explanation:

1. Total number of outcome= 6

Desired Outcomes= 5,6

No of desired outcomes = 2

P(A number greater than 4)= No of desired outcomes/ Total no of outcomes

= 2/6 = 1/3

2. Total number of outcome= 6

Desired Outcomes= 1,2,3,4

No of desired outcomes = 4

P(A number less than equal to 4) = No of desired outcomes/ Total no of outcomes

= 4/6 = 2/3

Answer 2

Given :

• A dice is thrown once .

To Find :

• Probability of getting a number greater than 4 .
• Probability of getting a number less than equal to 4 .

Solution :

$\longmapsto\tt{Total\:Outcomes=6}$

= 1 , 2 , 3 , 4 , 5 , 6

1. Probability of getting a number greater than 4 :

$\longmapsto\tt{Favourable\:Outcomes=2}$

= 5 and 6

$\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}$

$\longmapsto\tt{\cancel\dfrac{2}{6}}$

$\longmapsto\tt\bf{\dfrac{1}{3}}$

So , Probability of getting a number greater than 4 is 1/3 ....

_______________________

2. Probability of getting a number less than or equal to 4 :

$\longmapsto\tt{Favourable\:Outcomes=2}$

= 1 , 2 , 3 , 4

$\longmapsto\tt{Probability=\frac{No.\:of\:Fav.\:Outcomes}{Total\:No.\:of\:Outcomes}}$

$\longmapsto\tt{\cancel\dfrac{4}{6}}$

$\longmapsto\tt\bf{\dfrac{2}{3}}$

So , Probability of getting a number less than or equal to 4 is 2/3 ....